I needed hot water at around 80-85 Celsius to use with AeroPress. At the time, I didn't have a thermometer that goes higher than 50C. I know the room temperature and the temperature of near-boiling water (close to 100C ). The result: a calculator, for a cool (pun intended), practical use of thermodynamics.
The Question#
How many grams of ~20C water are needed to lower the temperature of 500g of ~100C water to ~85C?
Calculator#
Here is a calculator to do that for us. Go ahead and change the values for desired temperature and room/ambient temperature to get your answer.
Answer#
--
(Note: desired temperature should be between Cold and Hot water temperatures)
Detailed Solution#
Via convection, heat transfers from the hotter liquid to the colder.
$$QLostFromHot=QGainedFromCold$$
We can calculate heat transfer quantity using
$$Q=mC(ΔT)$$
Putting those two together we get
$$Q1 + Q2 = 0$$
$$M1•C•(T - T1) + M2•C•(T- T2) = 0$$
$$500•C•(85 - 100) + M2•C•(85 - 20) = 0$$
$$500•C•(-15) + M2•C•(65) = 0$$
$$M2•C•(65) = 500•C•(15)$$
And, solving for M2, we get
$$M2=\frac{500•(15)}{65}$$
$$M2=\frac{500•(15)}{65}$$
$$M2=\frac{7500}{65}=115.3g$$
I need to add 115.3g of room-temperature water.